Help with some C
PJ Hyett
pjhyett at gmail.com
Sat Apr 23 00:29:16 PDT 2005
I'm trying my hand with a little unix programming, but my second
execvp in main() below doesn't appear to be working correctly.
A sample call to this would be ./rungenerator 20 1 and the output is as follows:
parent: 27461
child: 27462
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38
child: 27463
the output should be:
parent: 27461
child: 27462
0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38
child: 27463
1 3 5...etc
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <fcntl.h>
int main(int argc, char* argv[]){
int fd[2];
pid_t child[2];
char *args[4];
if(argc != 3){
write(2,"Invalid # of arguments\n",23);
return 1;
}
args[0]="./generate1";
args[2]=argv[1];
args[3]=argv[2];
args[4]="0";
printf("parent: %ld\n",(long) getpid());
if(child[0] = fork())
child[1] = fork();
if(!child[0]){
printf("child: %ld\n",(long) getpid());
args[1]="even";
execvp(args[0],args);
}
if(!child[1]){
printf("child: %ld\n",(long) getpid());
args[1]="odd";
execvp(args[0],args);
}
return 0;
}
here's the code to generate1 if you're curious:
int main(int argc, char* argv[]){
int which, i, num, fd;
char buf[3];
if(argc != 4){
write(2,"Invalid # of arguments\n",23);
return 1;
}
if(!strcmp(argv[1],"odd"))
which=1;
else if(!strcmp(argv[1],"even"))
which=2;
else{
write(1,"Must be odd or even!\n",21);
return 2;
}
srand(which);
fd = atoi(argv[3]);
/* if we're counting 0 as even */
if(which==2)
write(fd,"0 ",2);
num = atoi(argv[2]) * 2;
for(i=which;i<num;i=i+2){
sprintf(buf,"%d ",i);
write(fd,buf,3);
}
write(fd,"\n",1);
return 0;
}
Any help would be appreciated. Thanks, PJ.
More information about the Users
mailing list