[issue1399] fnmatch(3) escapes '0' to '\'

[Stathis Kamperis (via DragonFly issue tracker)]

New submission from Stathis Kamperis <ekamperi at gmail.com>:

Salute.

Suppose that we supply fnmatch(3) with a pattern of the form "\" (that is '\'
followed by '0') without setting the FNM_NOESCAPE flag. Wouldn't the normal
thing to do is escape the terminating character and return just '0' ? Instead
'\' is returned. As if one has provided a pattern "\\".

This behavior is exhibited by NetBSD 5.0_STABLE, FreeBSD 7.2-RELEASE and
DragonFlyBSD HEAD.

On the other side sunOS 5.10 and Linux with a relatively recent glibc translate
the pattern to '0'.

You can check with the following snippet:

#include <assert.h>
#include <fnmatch.h>
#include <stdio.h>
#include <stdlib.h>

int main(void)
{
        int rv;

        rv = fnmatch(/* pattern */ "\\", "\\", 0);
        assert(rv == FNM_NOMATCH);

        printf("passed\n");

        return (EXIT_SUCCESS)
}

I've looked into the specs but couldn't find anything relevant.
Any thoughts ?

Cheers,
Stathis

----------
assignedto: Beket
files: 0001-fnmatch-3-Properly-escape-the-terminating-characte.patch
messages: 6737
nosy: Beket
priority: bug
status: unread
title: fnmatch(3) escapes '0' to '\'

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